Internet is up for a short time. I'll make the most of it.
So, I've been thinking. altering frequency isn't possible with an analog device like the ones I've been making. You would need to store the signal in order to manipulate it in anyway that involves changing frequency.
That doesn't mean other things cannot be done.
For one thing, I can try to make an equalizer. I've done that once already, but I could make it better.
I'm thinking about things I could do to the waveform. I could make the signal closer to a square wave (possibly a broken or robotic sound) by ramming the signal into the rails of an opamp.
I could use a capacitor to put a limit on the slew rate of a circuits output therefore making a sort of triangle wave, but that would probably make the audio signal totally unrecognizable. However, maybe if I use a diode or 2 I could make different slew rates for different changes in voltage (positive verses negative). Maybe that would make the audio recognizable.
I don't know, but I'll simulate it, and when I get the parts I'll build it.
I could also make a garbled sound by changing the amplitude of the output rapidly, I think.
Ok, I'm going to post and then edit this.
Edit: An Explanation of the circuits:
Starting with the bottom circuit, V2 is intended to represent an audio input signal to the circuit coming from an mp3 player.
The voltage (or potential) at the right of the opamp will be -2 times the voltage at the positive node of V2.
So, the voltage at the positive end of V2 will vary between + and -1 volt. One might think that you can simply amplify this signal and send it through the LED but that won't work. First of all, the receiver would not be able to tell the difference between a positive voltage and a negative one. Also, LED's are one way; they don't work with negative voltages. So, ya, we need a positive signal at all times.
So, I know that the max voltage will be - or + 4.5 V so I set + 4.5 to be the voltage at one end of the diode ( the 50k resistor). This way the voltage across the diode will always be positive.
The power supply is the 9 volt battery V3 connected to those 2 resistors which divide the voltage so that I can have + and - voltages relative to some node ( the ground node). Ideally I want those resistances to be zero but the need to be something, so its not a perfect supply, but hey, what is? Seriously, what is? Nothing!
As long as most of the other resistors are a lot more than 1k (or whatever I decide to make them) the circuit will work fine.
The receiver is the more interesting circuit. It needs to take a signal which will come through as a purely positive voltage and turn it into a positive and negative voltage. The interesting part is choosing an ideal 0 voltage, because this voltage will change depending on how far away the receiver is from the sender.
So what I did is simply amplify the signal the same way I did before except I now use the large capacitor C1 and large resistor R11 to
slowly take on the same voltage as the output. Because it is so slow at doing this, it will not change when there is a high voltage or change when there is a low voltage. It will instead slowly find the middle between the high and low voltages.
Because the capacitor holds our "average voltage" our output is the voltage difference between our amplified input and our C11 voltage.
Note, when I said slowly I mean like 1 10th or 1 60th of a second which is slow compared to the period of an audio signal in the audible range.
BTW, TheComet, what is that picture supposed to be? I don't know the device near the bottom there.
I thought you might mean something like this from your message.
Not be, well, a smart@$$ but I figured I'd mention that the diode there must is probably a silicon diode.
I've just heard a lot about this stuff so I notice it impulsively.
One can guess by seeing the strange choice in resistance which indicates that they want a clean current number like 1mA which causes the voltage across the diode to be .7V which is typical for a silicon diode when forward biased.