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DarkBASIC Professional Discussion / Rounding a float to the second place?

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Ryeguy457
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Posted: 13th Oct 2002 09:22
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How can I round a float number to the second place? Like if I had 126.6261, how would I round it to 126.63?
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Zed
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Posted: 13th Oct 2002 11:49
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One way would be to convert it to a string, find the '.' then count 2 more digits. Convert your string back into a real value having ignored the extra digits. Now check the next digit in the string to see if its higher than 4 and if it is add 0.01 to the real value.

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swdave
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Posted: 13th Oct 2002 11:50
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126.6261 * 100 = 12662.61
int(12662.61) = 12662
12662 / 100 = 126.62

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Zed
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Posted: 13th Oct 2002 11:50
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Oh and the quicker way is to multiply the number by 100 then add 0.5 then get the int() of the number and divide this by 100.

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swdave
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Posted: 13th Oct 2002 12:08
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oops

126.6261 * 100 = 12662.61
int(12662.61) = 12662
12662 / 100 = 126.62
if 126.6261 - 126.62 >= 0.005 then add 0.01

a# = 126.6261
b# = a# * 100
i = int(b#)
c# = i / 100
if a# - c# >= 0.005 then c# = c# + 0.01

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