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Arabic to Roman
rem Arabic Numeral Conversion
rem Made by Sinani201
rem The DB Classic Programming Challenge Thread
REM CHANGE THIS TO YOUR SCREEN RESOLUTION
set display mode 1024,768,32
cls
rem Make an array to hold each place value, as well as the letter set associated with each place.
dim place$(4,3)
rem Fill in part 2 of the array
place$(1,1) = "I" : place$(1,2) = "V" : place$(1,3) = "X"
place$(2,1) = "X" : place$(2,2) = "L" : place$(2,3) = "C"
place$(3,1) = "C" : place$(3,2) = "D" : place$(3,3) = "M"
place$(4,1) = "M" : rem The program will not allow higher values
do
input "Give me an Arabic number to convert to Roman numerals: ",a
rem Check if the input is bad
if a > 3999
print "Too high!"
wait key
end
endif
if a < 1
print "Too low!"
wait key
end
endif
rem Convert the number to a string for easy parsing.
a$ = str$(a)
print "String version is " + a$
rem Get the amount of digits so we can tell how many time the program needs to work
workload = len(a$)
print "There are " + str$(workload) + " digits in your number"
for i = 1 to workload
rem Use a seperate value to represent individual digits.
p$ = right$(a$,1) : p = val(p$)
print "Working on current digit: " + str$(p)
rem Work!
work(place$(i,1),place$(i,2),place$(i,3),i,p)
rem Make the input smaller so that p will point to the next digit
a$ = left$(a$,workload - i)
next i
rem Add up all of the values and display it
finalresult$ = place$(4,0) + place$(3,0) + place$(2,0) + place$(1,0)
print "FINAL RESULT: " + finalresult$ + " (Press any key to restart)"
wait key
cls
rem Reset everything
place$(1,0) = "" : place$(2,0) = ""
place$(3,0) = "" : place$(4,0) = ""
loop
function work(one$,five$,ten$,place,value)
rem Skip this workload if there is nothing to do
if value = 0 then exitfunction
rem We can use this without checking its value, because the value gets checked anyways in addamount
addamount(one$,place,value)
rem Fill in the irregular numbers (from the Roman point of view)
if value = 4 then place$(place,0) = one$ + five$
if value = 9 then place$(place,0) = one$ + ten$
rem If the number is 5 or higher, make it easy for addamount to crunch the numbers
if value > 4 and value < 9
print "Value is greater than 4, proceeding to alternate method"
place$(place,0) = five$
print "Used character: " + five$ + " for this digit, adding more if necessary"
newvalue = value - 5
print "Using " + str$(newvalue) + " for input into addamount"
addamount(one$,place,newvalue)
endif
print "I got " + place$(place,0) + " for this digit."
endfunction
function addamount(letter$,place,value)
rem Simple check to make sure the number is OK for crunching
if value < 4
print "Input for addamount is less than 4, proceeding"
rem Loop to add more letters for higher numbers
print "Adding " + letter$ + str$(value) + "times"
for i=1 to value
place$(place,0) = place$(place,0) + letter$
next i
endif
endfunction
Roman to Arabic
rem Roman Numeral Conversion
rem Made by Sinani201
rem The DB Classic Programming Challenge Thread
rem Make an array to define the Roman digits
REM CHANGE THIS TO YOUR SCREEN RESOLUTION
set display mode 1024,768,32
cls
dim rlib$(4,3)
rlib$(1,1) = "I" : rlib$(1,2) = "V" : rlib$(1,3) = "X"
rlib$(2,1) = "X" : rlib$(2,2) = "L" : rlib$(2,3) = "C"
rlib$(3,1) = "C" : rlib$(3,2) = "D" : rlib$(3,3) = "M"
rlib$(4,1) = "M" : rem The program will not allow higher values.
rem Make an array to define the Arabic equivalent of the Roman digits
dim alib(4,3)
alib(1,1) = 1 : alib(1,2) = 5 : alib(1,3) = 10
alib(2,1) = 10 : alib(2,2) = 50 : alib(2,3) = 100
alib(3,1) = 100 : alib(3,2) = 500 : alib(3,3) = 1000
alib(4,1) = 1000: rem The program will not allow higher values.
input "Give me a Roman numeral to convert to Arabic numerals: ",a$
a$ = upper$(a$)
print "I got " + a$ + " as your input."
workload = len(a$)
rem Process each digit individually.
for test = 1 to 4
p$ = right$(a$,1)
print "Current value is " + a$ + ". Each process will cut off one or two digits depending on the number. Pointing at " + p$ + "."
one$ = rlib$(test,1)
five$ = rlib$(test,2)
ten$ = rlib$(test,3)
before$ = charBefore$(a$)
print "Checking to see if " + p$ + " is " + rlib$(test,1)+", "+rlib$(test,2)+", or "+rlib$(test,3)
select p$
case one$
inc output, alib(test,1)
cutOff = 1 : redo = 1
print p$ + " is equal to " + str$(alib(test,1)) + ". This place will be tested again in case " + rlib$(test,1) + " is repeated (e.g., III). " + str$(alib(test,1)) + " has been added to the output."
endcase
case five$
print p$ + " is equal to " + str$(alib(test,2)) + ". Checking to see if there is a number of less rank behind it."
rem Check if the number before is 1
if one$ = before$
print rlib$(test,1) + " is before " + p$ + ". Adding " + str$(alib(test,2) - alib(test,1)) + " to the output."
inc output, alib(test,2) - alib(test,1)
cutOff = 2
else
print "Nothing is before " + rlib$(test,2) + ". Adding " + str$(alib(test,2)) + " to the output."
inc output, alib(test,2)
cutOff = 1
endif
endcase
case ten$
print p$ + " is equal to " + str$(alib(test,3)) + ". Checking to see if there is a number of less rank behind it."
rem Check if the number before is 1
if before$ = one$
print "OK, there is. Adding " + str$(alib(test,3)-alib(test,1)) + " to the output."
inc output, alib(test,3) - alib(test,1)
cutOff = 2
else
print "OK, there isn't. I wont do anything because the next test will be able to catch the number itself and then add it to the output."
endif
endcase
endselect
print "Finished this test. Current output is " + str$(output) + ". Cutting out " + str$(cutOff) + " from the number."
if cutOff = len(a$) then exit
rem Cut off numbers if necessary
if cutOff <> 0
a$ = left$(a$,len(a$)-cutOff)
endif
if redo = 1 then dec test
cutOff = 0
redo = 0
next test
print "FINAL OUTPUT: " + str$(output)
wait key
end
function charBefore$(full$)
output$ = left$(right$(full$,2),1)
endfunction output$
Both (USE THIS!!)
rem Roman Numeral Conversion
rem Made by Sinani201
rem The DB Classic Programming Challenge Thread
rem Make an array to define the Roman digits
REM CHANGE THIS TO YOUR SCREEN RESOLUTION
set display mode 1440,900,32
rem Set this to 0 if the debug info is longer than your screen.
debug = 1
cls
rem Make an array to hold the Roman digits, name it Roman Library (rlib)
dim rlib$(4,3)
rlib$(1,1) = "I" : rlib$(1,2) = "V" : rlib$(1,3) = "X"
rlib$(2,1) = "X" : rlib$(2,2) = "L" : rlib$(2,3) = "C"
rlib$(3,1) = "C" : rlib$(3,2) = "D" : rlib$(3,3) = "M"
rlib$(4,1) = "M" : rem The program will not allow higher values.
rem Make an array to define the Arabic equivalent of the Roman digits, name it Arabic Library (alib)
dim alib(4,3)
alib(1,1) = 1 : alib(1,2) = 5 : alib(1,3) = 10
alib(2,1) = 10 : alib(2,2) = 50 : alib(2,3) = 100
alib(3,1) = 100 : alib(3,2) = 500 : alib(3,3) = 1000
alib(4,1) = 1000: rem The program will not allow higher values.
do
input "Give me a Roman or Arabic number and I will convert it: ",a$
ab$=a$
if val(a$) = 0 then gosub r2a else gosub a2r
printc " (Press any key to restart)"
wait key
rem Reset everything
rlib$(1,0) = "" : rlib$(2,0) = ""
rlib$(3,0) = "" : rlib$(4,0) = ""
output=0
cls
loop
r2a:
a$ = upper$(a$)
ab$ = a$
print "I got " + a$ + " as your input."
workload = len(a$)
rem Process each digit individually.
for test = 1 to 4
p$ = right$(a$,1)
print "Current value is " + a$ + ". Each process will cut off one or two digits depending on the number. Pointing at " + p$ + "."
one$ = rlib$(test,1)
five$ = rlib$(test,2)
ten$ = rlib$(test,3)
before$ = charBefore$(a$)
print "Checking to see if " + p$ + " is " + rlib$(test,1)+", "+rlib$(test,2)+", or "+rlib$(test,3)
select p$
case one$
inc output, alib(test,1)
cutOff = 1 : redo = 1
print p$ + " is equal to " + str$(alib(test,1)) + ". This place will be tested again in case " + rlib$(test,1) + " is repeated (e.g., III). " + str$(alib(test,1)) + " has been added to the output."
endcase
case five$
print p$ + " is equal to " + str$(alib(test,2)) + ". Checking to see if there is a number of less rank behind it."
rem Check if the number before is 1
if one$ = before$
print rlib$(test,1) + " is before " + p$ + ". Adding " + str$(alib(test,2) - alib(test,1)) + " to the output."
inc output, alib(test,2) - alib(test,1)
cutOff = 2
else
print "Nothing is before " + rlib$(test,2) + ". Adding " + str$(alib(test,2)) + " to the output."
inc output, alib(test,2)
cutOff = 1
endif
endcase
case ten$
print p$ + " is equal to " + str$(alib(test,3)) + ". Checking to see if there is a number of less rank behind it."
rem Check if the number before is 1
if before$ = one$
print "OK, there is. Adding " + str$(alib(test,3)-alib(test,1)) + " to the output."
inc output, alib(test,3) - alib(test,1)
cutOff = 2
else
print "OK, there isn't. I wont do anything because the next test will be able to catch the number itself and then add it to the output."
endif
endcase
endselect
print "Finished this test. Current output is " + str$(output) + ". Cutting out " + str$(cutOff) + " from the number."
if cutOff = len(a$) then exit
rem Cut off numbers if necessary
if cutOff <> 0
a$ = left$(a$,len(a$)-cutOff)
endif
if redo = 1 then dec test
cutOff = 0
redo = 0
next test
if debug = 0
cls
print "Input was " + ab$
endif
print "FINAL RESULT: " + str$(output)
return
a2r:
a = val(a$)
rem Check if the input is bad
if a > 3999
print "Too high!"
wait key
end
endif
if a < 1
print "Too low!"
wait key
end
endif
rem Convert the number to a string for easy parsing.
a$ = str$(a)
print "String version is " + a$
rem Get the amount of digits so we can tell how many time the program needs to work
workload = len(a$)
print "There are " + str$(workload) + " digits in your number"
for i = 1 to workload
rem Use a seperate value to represent individual digits.
p$ = right$(a$,1) : p = val(p$)
print "Working on current digit: " + str$(p)
rem Work!
work(rlib$(i,1),rlib$(i,2),rlib$(i,3),i,p)
rem Make the input smaller so that p will point to the next digit
a$ = left$(a$,workload - i)
next i
rem Add up all of the values and display it
finalresult$ = rlib$(4,0) + rlib$(3,0) + rlib$(2,0) + rlib$(1,0)
if debug = 0
cls
print "Input was " + ab$
endif
print "FINAL RESULT: " + finalresult$
return
function charBefore$(full$)
output$ = left$(right$(full$,2),1)
endfunction output$
function addamount(letter$,place,value)
rem Simple check to make sure the number is OK for crunching
if value < 4
print "Input for addamount is less than 4, proceeding"
rem Loop to add more letters for higher numbers
print "Adding " + letter$ + str$(value) + "times"
for i=1 to value
rlib$(place,0) = rlib$(place,0) + letter$
next i
endif
endfunction
function work(one$,five$,ten$,place,value)
rem Skip this workload if there is nothing to do
if value = 0 then exitfunction
rem We can use this without checking its value, because the value gets checked anyways in addamount
addamount(one$,place,value)
rem Fill in the irregular numbers (from the Roman point of view)
if value = 4 then rlib$(place,0) = one$ + five$
if value = 9 then rlib$(place,0) = one$ + ten$
rem If the number is 5 or higher, make it easy for addamount to crunch the numbers
if value > 4 and value < 9
print "Value is greater than 4, proceeding to alternate method"
rlib$(place,0) = five$
print "Used character: " + five$ + " for this digit, adding more if necessary"
newvalue = value - 5
print "Using " + str$(newvalue) + " for input into addamount"
addamount(one$,place,newvalue)
endif
print "I got " + rlib$(place,0) + " for this digit."
endfunction
