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Geek Culture / I just discovered something freaky...

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Zotoaster
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Location: Scotland
Posted: 14th May 2007 05:31
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I'm probably totally wrong, but I can't see where. You guys tell me heh.

It seems that we are all moving at the exact same speed, all the time. Faster than light at that! Heheh.

Proof:

E = 0.5mv ^ 2
E = mc ^ 2

Put them together:

0.5mv ^ 2 = mc ^ 2

Divide through by m:

0.5v ^ 2 = c ^ 2

Multiply throughout by 2:

v ^ 2 = 2c ^ 2

so v = sqrt( 2c ^ 2)

Since c = 3e8:

sqrt( 2c ^ 2) = 6e8,

so:

v = 6e8 m/s

!!!

Light (c) is only 3e8 m/s..


I don't see where I have gone wrong here, but, well, if I _havent_, then that would be odd, lol.

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LD52
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Posted: 14th May 2007 05:41 Edited at: 14th May 2007 07:11
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Lol im not a math whiz so i don't know where you went wrong or if your wrong but yes if this was true then it's odd.
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Phaelax
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Posted: 14th May 2007 05:48 Edited at: 14th May 2007 05:50
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372,000 miles per second!

Something isn't right in the comparison, but I just can't put my finger on it exactly.

If you think about it, you're sort of making 'E' a constant, since C is a constant and you've eliminated the only other variable, mass.


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Gil Galvanti
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Posted: 14th May 2007 06:41 Edited at: 14th May 2007 06:48
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I don't think there's anything wrong with your math, but like Phaelax said, you made energy a constant, and it's not. It's like saying:

Distance=Velocity*Time
Distance=.5Velocity*Time

So distance = distance and velocity*time = .5velocity*time. You can't do it because the two distances are not necessarily the same, just like you can't do that with Energy .


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Zotoaster
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Posted: 14th May 2007 06:43 Edited at: 14th May 2007 06:45
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Quote: "Distance=.5Velocity*Time"


I dont see how that works lol.

[edit]

Anyway, many other equations have been made to put other equations together.

The only other thing I can think of, is that they are not the same type of energy, but as far as I've learned in physics class, they are!

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Gil Galvanti
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Posted: 14th May 2007 06:51 Edited at: 14th May 2007 06:57
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Quote: "I dont see how that works lol.
"

The given equation d=vt (distance equals velocity times time). So now we have the equation that d=.5vt (distance equals half of velocity times time). So plugin numbers:
v=10m/s
t=5s
d=vt
d=(10m/s)(5s)
d=50m

d=.5vt
d=.5(10m/s)(5s)
d=25m

According to your theory the two energies (distances) are always equal, even if you half velocity, and they aren't. As you can see
50m doesn't equal 25m, and your E doesn't equal your other E .

Quote: "Anyway, many other equations have been made to put other equations together."

Like what?

EDIT: Here's the same thing with your equation.
m=100kg
v=c
c=3x10^8m/s

E=mc^2
E=(100kg)(3x10^8m/s)^2
E=(100kg)(9x10^16m/s)
E=9x10^18m/s

E=.5mc^2
E=.5*100kg(3x10^8m/s)^2
E=50kg(9x10^16m/s)
E=4.5x10^17m/s

So your saying that
E=E
9x10^18m/s=4.5x10^17m/s
which is untrue .


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Cash Curtis II
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Location: Corpus Christi Texas
Posted: 14th May 2007 09:59 Edited at: 14th May 2007 10:00
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Quote: "Since c = 3e8:

sqrt( 2c ^ 2) = 6e8,

so:

v = 6e8 m/s

!!!"



Isn't the error there?

sqrt( 2c ^ 2) = 6e8,
sqrt( 2(3e8) ^ 2) = 6e8,
sqrt( 6e8 ^ 2) = 6e8,
Cancel the square root of the square...
6e8 = 6e8

You haven't solved for v at all, you've just proven that both sides are the same


Come see the WIP!
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Nicholas Thompson
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Location: Bognor Regis, UK
Posted: 14th May 2007 10:56
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Cash - do you square or multiply first? I cant remember the order... I thought you squared first... But then again, I got an E in A Level maths...

[center]
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Zotoaster
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Posted: 14th May 2007 11:57
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Gil,

d = 0.5vt isn't a valid equation though. It only gives you half the distance. E = 0.5mv^2 and E = mc^2 are both valid. We do this alot in physics, it works, trust me lol.

Cash,

v= sqrt( 2c^2 )

so v = sqrt( 6e8 ^2 )

so v = 6e8

...

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