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Newcomers DBPro Corner / Distance of 2 objects?

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retardnewb17
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Joined: 6th Oct 2011
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Posted: 22nd Oct 2011 11:33
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How would it be possible to get accurate number of two 3d object's distance?
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Hodgey
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Posted: 22nd Oct 2011 12:12
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I believe the formula is sqrt((x1 - x2)^2 + (y1 - y2)^2 + (z1 - z2)^2) but I'm not 100% sure.

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Darkzombies
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Posted: 22nd Oct 2011 18:53
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What about in 2d?

t is s gnat re h as ben destro ed by A m d
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IanM
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Posted: 22nd Oct 2011 20:14
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In 1D: sqrt((x1 - x2)^2)
In 2D: sqrt((x1 - x2)^2 + (y1 - y2)^2)
In 3D: sqrt((x1 - x2)^2 + (y1 - y2)^2 + (z1 - z2)^2)
In 4D: sqrt((x1 - x2)^2 + (y1 - y2)^2 + (z1 - z2)^2 + (w1 - w2)^2)

Ok, the 4D was kind of a joke as far as DBPro is concerned, but it's actually correct mathematically - I just wanted to make the progression obvious.

The 1D can be rewritten a little more efficiently: abs(x1 - x2)

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Hodgey
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Joined: 10th Oct 2009
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Posted: 23rd Oct 2011 04:05 Edited at: 23rd Oct 2011 04:05
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It looks like it keeps going as you add more dimensions. [href=en.wikipedia.org/wiki/Euclidean_distance]Here's[/href] what I mean.

How would you prove that though for 4+ dimensions? Mathematical induction?

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