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Newcomers DBPro Corner / Inverse Tangent - How?

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RossMills
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Posted: 4th Apr 2004 06:48
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This probably seems mundane... but I even asked the creator of DarkBASIC at the Uni and he didn't know...

So I was hoping a coder from here knew how to make an inverse tangent of a given number in DarkBASIC.

Thanks if you can.

Ross
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hyrichter
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Posted: 4th Apr 2004 08:27
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You use the atan() function which is the same as an inverse tangent.
And you use acos() for inverse cosine and asin() for inverse sine.

Hope this helped.
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BearCDPOLD
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Posted: 4th Apr 2004 09:19
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I dunno about DBPro, but DBC doesn't have atan, acos, and asin...

But remember the following:

Sine= Opposite/Hypotenuse
Cosine=Adjacent/Hypotenuse
Tangent=Opposite/Adjacent

To find the inverse of sin, multiply what you get out of sin() by the hypotenuse.

To find the inverse of cos, multiply what you get out of cos() by the hypotenuse.

To find the inverse of tan, multiplay what you get out of tan() by the adjacent.

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hyrichter
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Posted: 4th Apr 2004 09:25 Edited at: 4th Apr 2004 09:26
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My DBC has those commands. It's version 1.12. I tried it just a minute ago. I typed Print atan(1) and it showed 45.0085(I don't know why, it should be a precise 45 )
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BearCDPOLD
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Posted: 4th Apr 2004 09:26
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Awesome! You have my deepest gratitude, hyrichter.

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hyrichter
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Posted: 4th Apr 2004 09:28
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Thanks, but does anyone know why my computer gives 45.0085 for the inverse tangent of 45? Is it just a minor bug with DBC?
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BearCDPOLD
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Posted: 4th Apr 2004 09:33
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Hmmm.........I know tan(45) is 1. It's probably just the way the processor handles the math routines, same answer comes up when I run it. Integer truncating should help with that, since 99% of the time when dealing with trig you need your degrees values as ints.

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IanM
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Posted: 4th Apr 2004 13:52
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No, it's not a bug. It's a limitation of the floating point system used by the processor, combined with compressing the floats to 4 bytes from the 10 it uses internally.

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BearCDPOLD
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Posted: 4th Apr 2004 22:29
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Thanks boatloads for the enlightenment IanM

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