hills with small code? - GameCreators Forum

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doom on cats

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Posted: 5th Apr 2005 10:34

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how can i make a 10,000 sized matrix one great huge steadily growing hill without coding every single matrix square?

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Neofish

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Posted: 5th Apr 2005 22:07

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make matrix 1,10000,10000,1000,1000

for a=1 to 1000
   for b=1 to 1000
      set matrix height 1,a,b,c
      inc c
   next b
next a

Is that what you mean? I haven't compiled that but I think it's right

Also if you want the slope to incease you can have c^2 (c squared) or something similar when setting the height.

http://dbgamezone.com/pulse / http://neofish.dbspot.com <- "Ignore" the ads

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Sven B

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Posted: 6th Apr 2005 02:39

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i think he wants the highest point in the matrix in the middle of the screen...

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Sven B

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Posted: 6th Apr 2005 02:39

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in the middle of the matrix i mean...

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Underworld 1020

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Posted: 6th Apr 2005 09:16

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Well, in that case you would do the same thing again just dec the varible this time.

The finished code would look like this:

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make matrix 1,10000,10000,1000,1000

for a=1 to 499
   for b=1 to 499
      set matrix height 1,a,b,c
      inc c
   next b
next a

for a=500 to 1000
   for b=500 to 1000
      set matrix height 1,a,b,c
      dec c
   next b
next a

Check Out My Site Here: http://www.freewebs.com/underworld1020/

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ionstream

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Posted: 6th Apr 2005 11:29

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Quote: "without coding"

Well, none of us have a magic wand, so youre gonna have to go with coding.

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Sven B

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Posted: 6th Apr 2005 18:08

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I made a little code snippet in DBC so u can save ur matrix as an image. Maybe that could be helpfull...

http://forum.thegamecreators.com/?m=forum_view&t=51813&b=6

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Underworld 1020

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Posted: 6th Apr 2005 21:14

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Well, if you want you could just use a matrix editor like Matedit or Magic World. They work pretty good, but if you want to gain skill then I would suggest doing it by hand, like with the code that Neofish posted. But you could do it either way.

Check Out My Site Here: http://www.freewebs.com/underworld1020/

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Benjamin

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Posted: 7th Apr 2005 00:00

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Is this sort of what you want?

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TILEAMOUNTX = 10
TILEAMOUNTZ = 10
STEEPNESS# = 2.5

make matrix 1,1000,1000,TILEAMOUNTX,TILEAMOUNTZ

for x=0 to TILEAMOUNTX
for z=0 to TILEAMOUNTZ
height# = sqrt( abs(((TILEAMOUNTX/2)-x))^2 + abs(((TILEAMOUNTZ/2)-z))^2)
set matrix height 1,x,z,0-(height#^STEEPNESS#)+rnd(20)
next z
next x

update matrix 1